16m^2+80m+100=0

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Solution for 16m^2+80m+100=0 equation: 



16m^2+80m+100=0

a = 16; b = 80; c = +100;
Δ = b2-4ac
Δ = 802-4·16·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{-80}{32}=-2+1/2$

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